P(x)=-18x^2-48x

Solution for P(x)=-18x^2-48x equation:

(P)=-18P^2-48P

We move all terms to the left:

(P)-(-18P^2-48P)=0

We get rid of parentheses

18P^2+48P+P=0

We add all the numbers together, and all the variables

18P^2+49P=0

a = 18; b = 49; c = 0;
Δ = b2-4ac
Δ = 492-4·18·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-49}{2*18}=\frac{-98}{36}
=-2+13/18
$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+49}{2*18}=\frac{0}{36}
=0
$